A random variable X takes the values 0, 1 and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) We know that the sum of probabilities for all possible values of a random variable is $1$. Given $P(X=0) = 0.4$. Since $P(X=0) + P(X=1) + P(X=2) =

Vedclass · Accepted Answer

$0.9$

Vedclass · Answer

(D) We know that the sum of probabilities for all possible values of a random variable is $1$. Given $P(X=0) = 0.4$. Since $P(X=0) + P(X=1) + P(X=2) = 1$,we have $0.4 + P(X=1) + P(X=2) = 1$. This implies $P(X=1) + P(X=2) = 0.6$. Given $P(X=1) = P(X=2)$,let $P(X=1) = P(X=2) = p$. Then $p + p = 0.6 \Rightarrow 2p = 0.6 \Rightarrow p = 0.3$. Thus,$P(X=1) = 0.3$ and $P(X=2) = 0.3$. The mean of a random variable $X$ is given by $E(X) = \sum x_i P(X=x_i)$. $E(X) = (0 	imes P(X=0)) + (1 	imes P(X=1)) + (2 	imes P(X=2))$. $E(X) = (0 	imes 0.4) + (1 	imes 0.3) + (2 	imes 0.3)$. $E(X) = 0 + 0.3 + 0.6 = 0.9$.

$A$ random variable $X$ takes the values $0, 1$ and $2$. If $P(X=1)=P(X=2)$ and $P(X=0)=0.4$,then the mean of the random variable $X$ is

Similar Questions

Which one of the following salts gives an acidic solution in water?

Which of the following is a fossil pteridophyte?

The point of contact of the circles $x^2+y^2+2x+2y+1=0$ and $x^2+y^2-2x+2y+1=0$ is

$AgNO_3 \xrightarrow{\Delta} (W) + (X) + O_2$
$(X) + H_2O \to HNO_2 + HNO_3$
$(W) + HNO_3 \to (Y) + NO + H_2O$
$(Y) + Na_2S_2O_3 (\text{excess}) \to (Z) + NaNO_3$
Identify $(W)$ to $(Z)$.

The product of the lengths of the perpendiculars from any point on the hyperbola $x^2 - y^2 = 8$ to its asymptotes is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module