$\mathop {\lim }\limits_{x \to 0} \frac{\sin 2x}{x} = $

  • A
    $0$
  • B
    $1$
  • C
    $1/2$
  • D
    $2$

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Similar Questions

$\mathop {\lim }\limits_{x \to 0} \frac{{x\tan 2x - 2x\tan x}}{{{{\left( {1 - \cos 2x} \right)}^2}}}$ ની કિંમત શોધો.

$\lim _{x \rightarrow 0} \left( \frac{\sin (\pi \cos ^2 x)}{x^2} \right) = $

$\mathop {\lim }\limits_{\theta \to 0} \frac{{4\theta (\tan \theta - \sin \theta )}}{{{{(1 - \cos 2\theta )}^2}}}$ ની કિંમત શું છે?

Difficult
View Solution

જો $f(x) = -(\sin^2 x + \cos^5 x)$ હોય,તો $\lim_{x \rightarrow 0} \frac{f'(x)}{x}$ શોધો.

$\mathop {\lim }\limits_{x \to 1} \frac{{{x^2} - 1}}{{{{\sin }^2}x + \cos x \cos (x + 2) - {{\cos }^2}(x + 1)}}$ ની કિંમત શોધો.

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