$\mathop {\lim }\limits_{x \to 0} \frac{{{x^3}}}{{\sin {x^2}}} = $

  • A
    $0$
  • B
    $\frac{1}{3}$
  • C
    $3$
  • D
    $\frac{1}{2}$

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$\mathop {\lim }\limits_{x \to 0} \frac{{\sin (\pi {{\cos }^2}x)}}{{{x^2}}} = $

$\lim _{x \rightarrow 0} \frac{\sin \left(\pi \cos ^2 x\right)}{x^2}$ ની કિંમત શોધો.

$\lim _{x \rightarrow 0} \left( \frac{\sin (\pi \cos ^2 x)}{x^2} \right) = $

$\lim _{x \rightarrow 0} \frac{x \tan 2 x-2 x \tan x}{(1-\cos 3 x)(\operatorname{cosec} x-\cot x)^2}=$

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