$A$ moving coil galvanometer of resistance $100 \ \Omega$ shows a full scale deflection for a current of $1 \ mA$. The value of shunt resistance required to convert this galvanometer into an ammeter, showing full scale deflection for a current of $5 \ mA$, is . . . . . . $\Omega$.

The scale of a galvanometer is divided into $100$ equal divisions. It has a current sensitivity of $10 \text{ div./mA}$ and a voltage sensitivity of $4 \text{ div./mV}$. The resistance of the galvanometer is: (in $\Omega$)

$A$ moving coil galvanometer has $100$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \ V$,the resistance in Ohm's needed to be connected in series with the coil will be

$A$ moving coil galvanometer allows a full-scale current of $10^{-4} \ A$. $A$ series resistance of $2 \ M\Omega$ is required to convert the above galvanometer into a voltmeter of range $0-5 \ V$. Therefore,the value of shunt resistance required to convert the above galvanometer into an ammeter of range $0-10 \ mA$ is .... $\Omega$.

The deflection in a moving coil galvanometer falls from $50$ divisions to $10$ divisions,when a shunt of $12 \Omega$ is connected with it. The resistance of the galvanometer coil is . . . . . . . (in $\Omega$)

Assertion: To convert a galvanometer into an ammeter,a small resistance is connected in parallel with it.
Reason: The small resistance increases the combined resistance of the combination.