$A$ metal rod of length $L$ rotates about one end at origin with a uniform angular velocity $\omega$. The magnetic field radially falls off as $B(r) = B_0 e^{-\lambda r}$; $\lambda$ being a positive constant. The emf induced (neglecting the centripetal force on electrons in the rod) is :

  • A
    $B_0 \omega [\frac{1}{\lambda^2} - e^{-\lambda L} (\frac{1}{\lambda^2} + \frac{L}{\lambda})]$
  • B
    $B_0 \omega [\frac{1}{\lambda^2} + e^{-\lambda L} (\frac{1}{\lambda^2} + \frac{L}{\lambda})]$
  • C
    $B_0 \omega [\frac{4}{\lambda^2} - e^{-2\lambda L} (\frac{1}{\lambda^2} + \frac{2L}{\lambda})]$
  • D
    $B_0 \omega [\frac{3}{\lambda^2} - e^{-3\lambda L} (\frac{3}{\lambda^2} + \frac{L}{\lambda})]$

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Similar Questions

$A$ metallic rod of length $20 \,cm$ is placed in the North-South direction and is moved at a constant speed of $20 \,m/s$ towards the East. The horizontal component of the Earth's magnetic field at that place is $4 \times 10^{-3} \,T$ and the angle of dip is $45^{\circ}$. The emf induced in the rod is ............. $mV$.

$A$ long metal rod of length $L$ completes the circuit as shown. The area of the circuit is perpendicular to the magnetic field $B$. The total resistance of the circuit is $R$. The force needed to move the rod in the direction as shown with a constant speed $V$ is:

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Consider a metal ball of radius $r$ moving at a constant velocity $v$ in a uniform magnetic field of induction $\vec{B}$. Assuming that the direction of velocity forms an angle $\alpha$ with the direction of $\vec{B}$,the maximum potential difference between points on the ball is

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