$A$ cuboid has volume $V = l \times l \times \sqrt{l} = l^{2.5}$, where $l$ is the length of one side. When the length $l$ is measured by a meter scale of least count $1 \text{ mm}$, the relative percentage error in the measurement of its volume is $6.25\%$. Then the relative percentage error in measurement of its length and the value of the length $l$ is:

  • A
    $2\%$ and $2 \text{ cm}$
  • B
    $5\%$ and $4 \text{ cm}$
  • C
    $8\%$ and $3.6 \text{ cm}$
  • D
    $1\%$ and $3 \text{ cm}$

Explore More

Similar Questions

The maximum percentage errors in the measurement of mass $(M)$,radius $(R)$,and angular velocity $(\omega)$ of a ring are $2 \%$,$1 \%$,and $1 \%$ respectively. Find the maximum percentage error in the measurement of its angular momentum $(J = I \omega)$ about its geometrical axis. (in $\%$)

During Searle's experiment,the zero of the Vernier scale lies between $3.20 \times 10^{-2} \text{ m}$ and $3.25 \times 10^{-2} \text{ m}$ of the main scale. The $20^{\text{th}}$ division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of $2 \text{ kg}$ is applied to the wire,the zero of the Vernier scale still lies between $3.20 \times 10^{-2} \text{ m}$ and $3.25 \times 10^{-2} \text{ m}$ of the main scale,but now the $45^{\text{th}}$ division of the Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is $2 \text{ m}$ and its cross-sectional area is $8 \times 10^{-7} \text{ m}^2$. The least count of the Vernier scale is $1.0 \times 10^{-5} \text{ m}$. The maximum percentage error in the Young's modulus of the wire is:

If there is a positive error of $50\%$ in the measurement of velocity of a body,then the error in the measurement of kinetic energy is .............. $\%$

The radius of a sphere is $(5.3 \pm 0.1) \, cm$. The percentage error in its volume is

The radius $(r)$,length $(l)$,and resistance $(R)$ of a metal wire were measured in the laboratory as:
$r = (0.35 \pm 0.05) \text{ cm}$
$R = (100 \pm 10) \text{ } \Omega$
$l = (15 \pm 0.2) \text{ cm}$
The percentage error in the resistivity of the material of the wire is: (in $\%$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo