$\int \frac{(\tan^{-1} x)^3}{1 + x^2} \, dx = $

  • A
    $\frac{(\tan^{-1} x)^4}{4} + c$
  • B
    $\frac{(\tan^{-1} x)^4}{4} + c$
  • C
    $2 \tan^{-1} x + c$
  • D
    $2 (\tan^{-1} x)^2 + c$

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