int_0^{b - c} f''(x + a) , dx = | vedclass

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(B) To evaluate the integral $\int_0^{b - c} f''(x + a) \, dx$,we use the Fundamental Theorem of Calculus.Let $u = x + a$,then $du = dx$.When $x = 0$,

Vedclass · Accepted Answer

$f'(b - c + a) - f'(a)$

Vedclass · Answer

(B) To evaluate the integral $\int_0^{b - c} f''(x + a) \, dx$,we use the Fundamental Theorem of Calculus.Let $u = x + a$,then $du = dx$.When $x = 0$,$u = a$.When $x = b - c$,$u = b - c + a$.The integral becomes:$\int_a^{b - c + a} f''(u) \, du$Since the antiderivative of $f''(u)$ is $f'(u)$,we have:$[f'(u)]_a^{b - c + a} = f'(b - c + a) - f'(a)$.

$\int_0^{b - c} f''(x + a) \, dx = $

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