When the $F_1$ hybrid $Tt$ is crossed with the recessive parent $tt$,it is a case of....

$A$ tobacco plant which is heterozygous for albinism ($a$ recessive character) is self-pollinated. If $1200$ seeds are subsequently germinated,how many of the seedlings would have the parental genotype?

Find out the percentage of dominant phenotype in a cross between $Pp$ and $Pp$. ($P$ = dominant,$p$ = recessive) (in $, \%$)

In the case of inheritance of one gene,the phenotypic ratio of $3:1$ can be explained on the basis of which of the following?

Expected children of a blue-eyed (recessive) woman and brown-eyed (dominant) man who had a blue-eyed mother are likely to be:

In garden pea,round shape of seeds is dominant over wrinkled shape. $A$ pea plant heterozygous for round shape of seed is selfed and $1600$ seeds produced during the cross are subsequently germinated. How many seedlings would have the parental phenotype?