Considering the reaction 3O_2 rightarrow 2O_3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction $3O_2 \rightarrow 2O_3$ has a positive enthalpy change $(\Delta H > 0)$,which means it is an endothermic process.Since the formation

Vedclass · Accepted Answer

Ozone is less stable than oxygen and ozone decomposes to form oxygen immediately.

Vedclass · Answer

(B) The reaction $3O_2 \rightarrow 2O_3$ has a positive enthalpy change $(\Delta H > 0)$,which means it is an endothermic process.Since the formation of $O_3$ from $O_2$ requires energy,$O_3$ is at a higher energy state than $O_2$.According to the principle of stability,substances at higher energy levels are less stable.Therefore,$O_3$ is less stable than $O_2$,and it tends to decompose back into $O_2$ to achieve a more stable,lower-energy state.

Considering the reaction $3O_2 \rightarrow 2O_3$; $\Delta H = +ve$,what can we conclude about the reaction?

Similar Questions

Average $C-H$ bond energy is $416 \ kJ \ mol^{-1}$. Which of the following is correct?

The compounds with negative heat of formation are known as:

$CuSO_{4(s)} + 5 H_2O_{(\ell)} \rightarrow CuSO_4 \cdot 5 H_2O_{(s)} ; \Delta H = -x \ kJ$. The value of $\Delta H$ represents:

When $10 \ g$ of methane is completely burnt in oxygen, the heat evolved is $560 \ kJ$. What is the heat of combustion (in $kJ \ mol^{-1}$) of methane?

The heats of formation of $CO_{2(g)}$,$H_2O_{(l)}$,and $CH_{4(g)}$ are $-94.0$,$-68.4$,and $-17.9 \ kcal$ respectively. The heat of combustion of methane is.....$kcal$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module