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(C) Let the mass of each substance be $W$. The number of moles of $X$ is $n_X = \frac{W}{30}$. The number of moles of $Y$ is $n_Y = \frac{W}{20}$. The

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$X_2Y_3$

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(C) Let the mass of each substance be $W$. The number of moles of $X$ is $n_X = \frac{W}{30}$. The number of moles of $Y$ is $n_Y = \frac{W}{20}$. The ratio of moles $n_X : n_Y = \frac{W}{30} : \frac{W}{20} = \frac{1}{3} : \frac{1}{2} = 2 : 3$. Thus,the empirical formula is $X_2Y_3$. The empirical formula weight is $(2 	imes 30) + (3 	imes 20) = 60 + 60 = 120$. Since the given molecular weight is $120$,the molecular formula is the same as the empirical formula,which is $X_2Y_3$.

Substances $X$ and $Y$ have the same mass. If their atomic weights are $30$ and $20$ respectively,and the molecular weight of the compound is $120$,what is the molecular formula of the compound?

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