What is the total number of electrons present | vedclass

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(B) Density = Mass / Volume. Mass of water = $1 \ g/mL 	imes 18 \ mL = 18 \ g$. Moles of water = $18 \ g / 18 \ g/mol = 1 \ mol$. $1 \ mol$ of $H_2O$

Vedclass · Accepted Answer

$6.022 	imes 10^{24}$

Vedclass · Answer

(B) Density = Mass / Volume. Mass of water = $1 \ g/mL 	imes 18 \ mL = 18 \ g$. Moles of water = $18 \ g / 18 \ g/mol = 1 \ mol$. $1 \ mol$ of $H_2O$ contains $6.022 	imes 10^{23}$ molecules of $H_2O$. Each $H_2O$ molecule contains $2$ electrons from $2H$ atoms and $8$ electrons from $1O$ atom,so total electrons per molecule = $2 + 8 = 10 \ e^-$. Total electrons = $1 \ mol 	imes 6.022 	imes 10^{23} 	ext{ molecules/mol} 	imes 10 	ext{ electrons/molecule} = 6.022 	imes 10^{24} \ e^-$.

What is the total number of electrons present in $18 \ mL$ of water? (Density of water = $1 \ g/mL$)

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