When an element forms its oxide,oxygen consti | vedclass

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(A) Given that oxygen is $20\%$ by weight in the oxide,the weight of the element is $100\% - 20\% = 80\%$.Let the total weight of the oxide be $100 \

Vedclass · Accepted Answer

$32$

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(A) Given that oxygen is $20\%$ by weight in the oxide,the weight of the element is $100\% - 20\% = 80\%$.Let the total weight of the oxide be $100 \ g$.Weight of element $(W_M)$ = $80 \ g$.Weight of oxygen $(W_O)$ = $20 \ g$.The equivalent weight $(E)$ of an element is given by the formula: $E = \frac{W_M}{W_O} 	imes 8$.Substituting the values: $E = \frac{80}{20} 	imes 8 = 4 	imes 8 = 32$.Thus,the equivalent weight of the element is $32$.

When an element forms its oxide,oxygen constitutes $20\%$ of its weight in the oxide. What is the equivalent weight of the element?

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