What should be the ratio of velocities of CH_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.For methane $(CH_4)$,$\lambda_{CH_4} = \frac{h}{m_{CH_4} 	imes v_{CH_4}}$.For oxyge

Vedclass · Accepted Answer

$2 : 1$

Vedclass · Answer

(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.For methane $(CH_4)$,$\lambda_{CH_4} = \frac{h}{m_{CH_4} 	imes v_{CH_4}}$.For oxygen $(O_2)$,$\lambda_{O_2} = \frac{h}{m_{O_2} 	imes v_{O_2}}$.Since the wavelengths are equal,$\lambda_{CH_4} = \lambda_{O_2}$.Therefore,$m_{CH_4} 	imes v_{CH_4} = m_{O_2} 	imes v_{O_2}$.$\frac{v_{CH_4}}{v_{O_2}} = \frac{m_{O_2}}{m_{CH_4}} = \frac{32}{16} = 2$.Thus,the ratio of velocities is $2 : 1$.

What should be the ratio of velocities of $CH_4$ and $O_2$ molecules so that they are associated with de Broglie waves of equal wavelength?

Similar Questions

Number of waves formed by a Bohr electron in one complete revolution in its third orbit is

The wavelength of an electron in the first orbit of a hydrogen atom is $3.3 \times 10^{-10} \ m$. The kinetic energy of the electron (in $J$) is:
$(h = 6.6 \times 10^{-34} \ Js, m_{e} = 9.0 \times 10^{-31} \ kg)$

Number of waves produced by an electron in one complete revolution in $n^{th}$ orbit is

The mass of a proton is $1.67 \times 10^{-27} \ kg$. If it is moving with a velocity of $10^3 \ m/s$,calculate its wavelength in nanometers.

Can the wave nature of ordinary objects be detected? Why?

Vedclass Test Series

Exam Paper Generator

Online Exam Module