For $AgCl$,$K_{sp} = 1.2 \times 10^{-10}$ and for $AgBr$,$K_{sp} = 3.5 \times 10^{-13}$. What is the relationship between their solubilities $(S)$?
- A$S$ of $AgBr < S$ of $AgCl$
- B$S$ of $AgBr > S$ of $AgCl$
- C$S$ of $AgBr = S$ of $AgCl$
- D$S$ of $AgCl = 10^6 \times S$ of $AgBr$
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