A radar has a power of 1 text{ kW} and operat | vedclass

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Question

(A) The maximum line-of-sight distance $d_M$ for a transmitter at height $h$ above the Earth's surface is given by the formula:$d_M = \sqrt{2hR}$Given

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(A) The maximum line-of-sight distance $d_M$ for a transmitter at height $h$ above the Earth's surface is given by the formula:$d_M = \sqrt{2hR}$Given:Height $h = 500 	ext{ m}$Earth's radius $R = 6.4 	imes 10^{6} 	ext{ m}$Substituting the values:$d_M = \sqrt{2 	imes 500 	imes 6.4 	imes 10^{6}}$$d_M = \sqrt{1000 	imes 6.4 	imes 10^{6}}$$d_M = \sqrt{6.4 	imes 10^{9}}$$d_M = \sqrt{6400 	imes 10^{6}}$$d_M = 80 	imes 10^{3} 	ext{ m}$$d_M = 80 	ext{ km}$Thus,the radar can detect objects up to a maximum distance of $80 	ext{ km}$.

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