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(B) According to Coulomb's law,the electrostatic force $F$ between the nucleus and the electron is given by $F = \frac{1}{4\pi\epsilon_0} \frac{Ze^2}{

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$F \propto 1/n^4$

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(B) According to Coulomb's law,the electrostatic force $F$ between the nucleus and the electron is given by $F = \frac{1}{4\pi\epsilon_0} \frac{Ze^2}{r^2}$.Since $F \propto \frac{1}{r^2}$,we need to find the relationship between the radius $r$ and the principal quantum number $n$.In the Bohr model,the radius of the $n$-th orbit is given by $r_n \propto n^2$.Substituting this into the force expression: $F \propto \frac{1}{(n^2)^2} = \frac{1}{n^4}$.Therefore,the force on the electron is proportional to $1/n^4$.

In the Bohr model of the hydrogen atom,the force on the electron is proportional to which power of the principal quantum number $n$?

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