Three capacitors of $2\ \mu F, 3\ \mu F$,and $6\ \mu F$ are connected in series with a $24\ V$ battery. The potential difference across the $6\ \mu F$ capacitor is .......... $V$.

Three capacitors of capacitance $1\ \mu F$,$2\ \mu F$,and $3\ \mu F$ are connected in series,and a potential difference of $11\ V$ is applied across the combination. The potential difference across the plates of the $1\ \mu F$ capacitor is......$V$.

Two capacitors of same capacity are first joined in series and then in parallel. The ratio of resultant capacity in series to that in parallel combination will be

How will you connect four capacitors,each of capacitance $4 \mu F$,to obtain an equivalent capacitance of $1.6 \mu F$?

Five capacitors,each of value $1 \mu F$,are connected as shown in the figure. The equivalent capacitance between $A$ and $B$ is (in $\mu F$)

In the arrangement of capacitors shown in the figure,if each capacitor is $9 pF$,then the effective capacitance between the points $A$ and $B$ is (in $pF$)