What will be the conductivity of a pure silic | vedclass

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(D) The conductivity $\sigma$ of an intrinsic semiconductor is given by the formula: $\sigma = n_i e (\mu_n + \mu_p)$.Here,$n_i = 1.072 	imes 10^{10}

Vedclass · Accepted Answer

$3.14 	imes 10^{-6} \ mho/cm$

Vedclass · Answer

(D) The conductivity $\sigma$ of an intrinsic semiconductor is given by the formula: $\sigma = n_i e (\mu_n + \mu_p)$.Here,$n_i = 1.072 	imes 10^{10} \ cm^{-3}$,$e = 1.6 	imes 10^{-19} \ C$,$\mu_n = 1350 \ cm^2/(V \cdot s)$,and $\mu_p = 480 \ cm^2/(V \cdot s)$.Substituting the values:$\sigma = (1.072 	imes 10^{10}) 	imes (1.6 	imes 10^{-19}) 	imes (1350 + 480)$$\sigma = (1.072 	imes 1.6 	imes 10^{-9}) 	imes (1830)$$\sigma = 1.7152 	imes 10^{-9} 	imes 1830$$\sigma \approx 3.1388 	imes 10^{-6} \ mho/cm \approx 3.14 	imes 10^{-6} \ mho/cm$.

What will be the conductivity of a pure silicon crystal at $300 \ K$? Given that the intrinsic carrier concentration is $1.072 \times 10^{10} \ cm^{-3}$ and at this temperature,the electron mobility $\mu_n = 1350 \ cm^2 / (V \cdot s)$ and hole mobility $\mu_p = 480 \ cm^2 / (V \cdot s)$.

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