In the given transistor circuit,the base current is $35 \ \mu A$. If the value of $V_{BE}$ is negligible,what is the value of $R_b$ in $k\Omega$?

An $N-P-N$ transistor in a common emitter mode is used as a simple voltage amplifier with a collector current of $4 \ mA$. The terminal of an $8 \ V$ battery is connected to the collector through a load resistance $R_L$ and to the base through a resistance $R_B$. The collector-emitter voltage $V_{CE} = 4 \ V$,base-emitter voltage $V_{BE} = 0.6 \ V$ and base current amplification factor $\beta_{d.c.} = 100$. Calculate the values of $R_L$ and $R_B$.

An $n-p-n$ transistor has three leads $A, B$ and $C$. Connecting $B$ and $C$ by moist fingers,$A$ to the positive lead of an ammeter,and $C$ to the negative lead of the ammeter,one finds large deflection. Then,$A, B$ and $C$ refer respectively to

For a common-emitter transistor amplifier, the current gain is $60$. If the emitter current is $6.6 \,mA$, then its base current is (in $\,mA$)

While a collector to emitter voltage is constant in a transistor, the collector current changes by $8.2 \,mA$ when the emitter current changes by $8.3 \,mA$. The value of forward current ratio is

The base current in a transistor circuit changes from $45 \mu A$ to $140 \mu A$. Accordingly, the collector current changes from $0.2 \text{ mA}$ to $4.0 \text{ mA}$. The gain in current is