(A) The angular width of a fringe in Young's double-slit experiment is given by $\beta_\theta = \frac{\lambda}{d}$.Since the angular width $\beta_\the

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Increase the wavelength by $589 \ \mathring A$.

(A) The angular width of a fringe in Young's double-slit experiment is given by $\beta_\theta = \frac{\lambda}{d}$.Since the angular width $\beta_\theta$ is directly proportional to the wavelength $\lambda$ (i.e.,$\beta_\theta \propto \lambda$),if the angular width is increased by $10\%$,the wavelength must also be increased by $10\%$.Given initial wavelength $\lambda = 5890 \ \mathring A$.The required change in wavelength $\Delta \lambda = 10\% \text{ of } \lambda = 5890 \times \frac{10}{100} = 589 \ \mathring A$.Therefore,the wavelength should be increased by $589 \ \mathring A$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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In a Young's double-slit experiment,sodium light of wavelength $5890 \ \mathring A$ is used,and the angular width of the fringe is found to be $0.20^\circ$. If the angular width is to be increased by $10\%$,what is the required change in the wavelength?

A
Increase the wavelength by $589 \ \mathring A$.
B
Decrease the wavelength by $589 \ \mathring A$.
C
Increase the wavelength by $6479 \ \mathring A$.
D
No change in wavelength is required.

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Wave Optics

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Young's Double Slit Experiment (YDSE)

In the Young's double-slit experiment, the spacing between two slits is $0.1 \, mm$. If the screen is kept at a distance of $1.0 \, m$ from the slits and the wavelength of light is $5000 \, \mathring{A}$, then the fringe width is ........ $cm$.

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In a Young's double-slit experiment,sources of equal intensities are used. The distance between the slits is $d$ and the wavelength of light used is $\lambda$ (where $\lambda \ll d$). Find the angular separation of the nearest points on either side of the central maximum where the intensity becomes half of the maximum value.

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In a Young's double-slit experiment,light of wavelength $5890 \ \mathring A$ is used,and the angular fringe width on the screen is $0.20^\circ$. If the entire apparatus is immersed in water,find the new angular fringe width. (Refractive index of water $\mu = 4/3$) (in $^\circ$)

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In Young's double slit experiment,the two slits act as coherent sources of equal amplitude $A$ and wavelength $\lambda$. In another experiment with the same setup,the two slits are sources of equal amplitude $A$ and wavelength $\lambda$ but are incoherent. The ratio of the intensity of light at the midpoint of the screen in the first case to that in the second case is:

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If the monochromatic source in Young's double slit experiment is replaced by white light,then

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In a Young's double-slit experiment,sodium light of wavelength $5890 \ \mathring A$ is used,and the angular width of the fringe is found to be $0.20^\circ$. If the angular width is to be increased by $10\%$,what is the required change in the wavelength?

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In the Young's double-slit experiment, the spacing between two slits is $0.1 \, mm$. If the screen is kept at a distance of $1.0 \, m$ from the slits and the wavelength of light is $5000 \, \mathring{A}$, then the fringe width is ........ $cm$.

In a Young's double-slit experiment,light of wavelength $5890 \ \mathring A$ is used,and the angular fringe width on the screen is $0.20^\circ$. If the entire apparatus is immersed in water,find the new angular fringe width. (Refractive index of water $\mu = 4/3$) (in $^\circ$)

If the monochromatic source in Young's double slit experiment is replaced by white light,then

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