If the Arithmetic Mean (AM) = 16 and the Harm | vedclass

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(A) We know the relationship between Arithmetic Mean $(AM)$,Geometric Mean $(GM)$,and Harmonic Mean $(HM)$ for two numbers is given by the formula: $G

Vedclass · Accepted Answer

$6\sqrt{7}$

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(A) We know the relationship between Arithmetic Mean $(AM)$,Geometric Mean $(GM)$,and Harmonic Mean $(HM)$ for two numbers is given by the formula: $GM^2 = AM 	imes HM$ Given: $AM = 16$ $HM = \frac{63}{4}$ Substituting the values: $GM^2 = 16 	imes \frac{63}{4}$ $GM^2 = 4 	imes 63$ $GM^2 = 252$ $GM = \sqrt{252}$ $GM = \sqrt{36 	imes 7}$ $GM = 6\sqrt{7}$ Therefore,the correct option is $A$.

If the Arithmetic Mean $(AM)$ $= 16$ and the Harmonic Mean $(HM)$ $= \frac{63}{4}$ for any two numbers,what will be the Geometric Mean $(GM)$?

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