sim (p Leftrightarrow q) = dots | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We know that $p \Leftrightarrow q$ is equivalent to $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$.Therefore,$\sim (p \Leftrightarrow q) = \sim

Vedclass · Accepted Answer

$(\sim p \wedge q) \vee (p \wedge \sim q)$

Vedclass · Answer

(C) We know that $p \Leftrightarrow q$ is equivalent to $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$.Therefore,$\sim (p \Leftrightarrow q) = \sim ((p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p))$.Using De Morgan's Law,$\sim (A \wedge B) = \sim A \vee \sim B$,we get:$\sim (p$ $\Rightarrow q) \vee \sim (q$ $\Rightarrow p)$.Since $\sim (p \Rightarrow q) \equiv p \wedge \sim q$,the expression becomes:$(p \wedge \sim q) \vee (q \wedge \sim p)$.

$\sim (p \Leftrightarrow q) = \dots$

Similar Questions

The minimum number of switches in the simplified form of the following switching circuit is

The negation of the inverse of $\sim p \rightarrow q$ is

The negation of the inverse of the statement $\sim p \lor q$ is...

The contrapositive of $(\sim p \wedge q) \rightarrow (q \wedge \sim r)$ is

The statement that is $TRUE$ among the following is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module