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(A) For a binomial distribution,the mean is given by $\mu = np$ and the variance is given by $\sigma^2 = npq$.Given that $np = 6$ and $npq = 4$.Dividi

Vedclass · Accepted Answer

$18$

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(A) For a binomial distribution,the mean is given by $\mu = np$ and the variance is given by $\sigma^2 = npq$.Given that $np = 6$ and $npq = 4$.Dividing the variance by the mean,we get:$\frac{npq}{np} = \frac{4}{6}$$q = \frac{2}{3}$Since $p + q = 1$,we have $p = 1 - q = 1 - \frac{2}{3} = \frac{1}{3}$.Substituting the value of $p$ into the mean equation:$np = 6$$n 	imes \frac{1}{3} = 6$$n = 6 	imes 3 = 18$.Therefore,the value of $n$ is $18$.

For a binomial distribution,the mean and variance are $6$ and $4$ respectively. Find the value of $n$.

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