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$KMnO_4$ acts as an oxidising agent in the neutral medium and gets reduced to $MnO_2$. What is the equivalent weight of $KMnO_4$ in a neutral medium?

What is the oxidation number of $Cl$ in $CaOCl_2$?

In alkaline condition,$KMnO_4$ reacts as follows:
$2KMnO_4 + 2KOH \to 2K_2MnO_4 + H_2O + O$
The equivalent weight of $KMnO_4$ is:

The oxidation state of each oxygen atom in $Na_{2}O_{2}$ is

The oxidation states of $Cr$ in $K_2Cr_2O_7$ and $CrO_5$ are, respectively:

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