The oxidation states of Cr in K_2Cr_2O_7 and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For $K_2Cr_2O_7$: Let the oxidation state of $Cr$ be $x$. $2(+1) + 2x + 7(-2) = 0$ $2 + 2x - 14 = 0$ $2x = 12$ $x = +6$ For $CrO_5$: This compound

Vedclass · Accepted Answer

$+6, +6$

Vedclass · Answer

(C) For $K_2Cr_2O_7$: Let the oxidation state of $Cr$ be $x$. $2(+1) + 2x + 7(-2) = 0$ $2 + 2x - 14 = 0$ $2x = 12$ $x = +6$ For $CrO_5$: This compound has a butterfly structure containing four peroxy oxygen atoms (each with $-1$ charge) and one oxo oxygen atom (with $-2$ charge). Let the oxidation state of $Cr$ be $x$. $x + 4(-1) + 1(-2) = 0$ $x - 4 - 2 = 0$ $x - 6 = 0$ $x = +6$ Thus, the oxidation states of $Cr$ in both compounds are $+6$.

The oxidation states of $Cr$ in $K_2Cr_2O_7$ and $CrO_5$ are, respectively:

Similar Questions

Identify the oxidation number of Sulphur in $SO_2$ and $SO_4^{2-}$ respectively.

Ozonolysis of $ClO_2$ produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is . . . . .

Oxidation state of nitrogen in nitric oxide is

An acidified solution of sodium thiosulfate is unstable because in thiosulfate,the two sulfur atoms are in:

What are the oxidation numbers of sulfur in $S_8$,$S_2F_2$,and $H_2S$ respectively?

Vedclass Test Series

Exam Paper Generator

Online Exam Module