An organic compound A reacts with NH_3 on hea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of $B$ with $Br_2$ and $KOH$ is the Hofmann bromamide degradation reaction,which converts an amide $(RCONH_2)$ into a primary amine $

Vedclass · Accepted Answer

$CH_3CH_2COOH$

Vedclass · Answer

(D) The reaction of $B$ with $Br_2$ and $KOH$ is the Hofmann bromamide degradation reaction,which converts an amide $(RCONH_2)$ into a primary amine $(RNH_2)$ with one carbon atom less.Given that the product is $CH_3CH_2NH_2$ (ethanamine),the amide $B$ must be $CH_3CH_2CONH_2$ (propanamide).Since $A$ reacts with $NH_3$ on heating to form propanamide $(B)$,$A$ must be propanoic acid $(CH_3CH_2COOH)$.The reaction sequence is: $CH_3CH_2COOH + NH_3$ $\xrightarrow{\Delta} CH_3CH_2CONH_2 (B)$ $\xrightarrow{Br_2/KOH} CH_3CH_2NH_2$.

An organic compound $A$ reacts with $NH_3$ on heating to give $B$. Compound $B$ reacts with $Br_2$ in the presence of $KOH$ to give $CH_3CH_2NH_2$. What is $A$?

Similar Questions

How will you convert:
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?

Primary and secondary amines can be distinguished by $:-$

An aromatic amine $(A)$ was treated with alcoholic potash and another compound $(Y)$ to form a foul-smelling gas with the formula $C_6H_5NC$. Compound $(Y)$ was formed by reacting a compound $(Z)$ with $Cl_2$ in the presence of slaked lime. The compound $(Z)$ is:

Which of the following statements is not true?

When $methyl$ $iodide$ is heated with $ammonia$,the product obtained is

Vedclass Test Series

Exam Paper Generator

Online Exam Module