The equation of the family of circles having the same radical axis as the circles $x^2 + y^2 = 4$ and $x^2 + y^2 + 2x + 4y = 6$ is:
- A$x^2 + y^2 + \lambda x + 2\lambda y - (4 + \lambda) = 0$
- B$x^2 + y^2 + \lambda(x - 2y - 1) = 0$
- C$x^2 + y^2 + \lambda(x + 2y - 4) = 1$
- D$x^2 + y^2 + 2\lambda x + \lambda y - (4 + \lambda) = 0$
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