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(D) The formula for the length of the perpendicular from a point $(x_1, y_1)$ to a line $Ax + By + C = 0$ is given by $d = \frac{|Ax_1 + By_1 + C|}{\s

Vedclass · Accepted Answer

$2$

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(D) The formula for the length of the perpendicular from a point $(x_1, y_1)$ to a line $Ax + By + C = 0$ is given by $d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}$.Given point $(x_1, y_1) = (2, 1)$ and line $3x - 4y + 8 = 0$.Here,$A = 3$,$B = -4$,and $C = 8$.Substituting these values into the formula:$d = \frac{|3(2) - 4(1) + 8|}{\sqrt{3^2 + (-4)^2}}$$d = \frac{|6 - 4 + 8|}{\sqrt{9 + 16}}$$d = \frac{|10|}{\sqrt{25}}$$d = \frac{10}{5} = 2$.Therefore,the length of the perpendicular is $2$.

Find the length of the perpendicular drawn from the point $(2, 1)$ to the line $3x - 4y + 8 = 0$.

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