If A(4, -3),B(3, -2),and C(2, 8) are the vert | vedclass

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(B) The centroid $(G)$ of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by the formula: $G = \left( \frac{x_1 + x_2 + x

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$3$

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(B) The centroid $(G)$ of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by the formula: $G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)$ Given vertices are $A(4, -3)$,$B(3, -2)$,and $C(2, 8)$. Substituting the values: $G = \left( \frac{4 + 3 + 2}{3}, \frac{-3 - 2 + 8}{3} \right)$ $G = \left( \frac{9}{3}, \frac{3}{3} \right) = (3, 1)$ The distance of a point $(x, y)$ from the $y$-axis is given by $|x|$. Therefore,the distance of the centroid $(3, 1)$ from the $y$-axis is $|3| = 3$ units.

If $A(4, -3)$,$B(3, -2)$,and $C(2, 8)$ are the vertices of a triangle,what is the distance of its centroid from the $y$-axis?

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