For what value of a is the function f(x) = a^ | vedclass

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(C) The function $f(x) = a^x$ is defined for $a > 0$ and $a 
eq 1$. To determine if the function is strictly increasing,we examine its derivative: $f

Vedclass · Accepted Answer

$a > 1$

Vedclass · Answer

(C) The function $f(x) = a^x$ is defined for $a > 0$ and $a 
eq 1$. To determine if the function is strictly increasing,we examine its derivative: $f'(x) = \frac{d}{dx}(a^x) = a^x \ln(a)$. For the function to be strictly increasing,we require $f'(x) > 0$ for all $x$. Since $a^x > 0$ for all $x$,the condition $f'(x) > 0$ is satisfied if $\ln(a) > 0$. This implies $a > e^0$,which means $a > 1$. Thus,the function $f(x) = a^x$ is strictly increasing when $a > 1$.

For what value of $a$ is the function $f(x) = a^x$ a strictly increasing function?

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