(B) The position of the particle is given by $x = a + bt^2$.The velocity $v$ is the time derivative of the position $x$:$v = \frac{dx}{dt} = \frac{d}{

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(B) The position of the particle is given by $x = a + bt^2$.The velocity $v$ is the time derivative of the position $x$:$v = \frac{dx}{dt} = \frac{d}{dt}(a + bt^2)$Since $a$ is a constant,its derivative is $0$:$v = 0 + 2bt = 2bt$Given $b = 3 \, cm/s^2$ and $t = 3 \, s$:$v = 2 \times 3 \times 3$$v = 18 \, cm/s$.

Class 11 Physics Motion in a Straight Line Instantaneous Velocity and Speed and Velocity-time Graph

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$A$ particle moves according to the equation $x = a + bt^2$,where $a = 15 \, cm$ and $b = 3 \, cm/s^2$. What is the velocity of the particle at $t = 3 \, s$ in $cm/s$?

A
$36$
B
$18$
C
$16$
D
$32$

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Motion in a Straight Line

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Instantaneous Velocity and Speed and Velocity-time Graph

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$A$ particle moves according to the equation $x = a + bt^2$,where $a = 15 \, cm$ and $b = 3 \, cm/s^2$. What is the velocity of the particle at $t = 3 \, s$ in $cm/s$?

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