$A$ car of mass $100 \, kg$ is moving with a velocity of $5 \, m/s$. The force required to stop it in $\frac{1}{10} \, s$ is . . . . . . $N$.

$A$ particle of mass $m$ at rest is acted upon by a force $P$ for a time $t$. Its kinetic energy after an interval $t$ is

$A$ body of mass $5 \; kg$ is acted upon by two perpendicular forces $8 \; N$ and $6 \; N$. Find the magnitude and direction of the acceleration of the body.

The magnitude of the external force acting on moving bodies can be known directly by

$A$ cricket player catches a ball of mass $120 \,g$ moving with $25 \,m/s$ speed. If the catching process is completed in $0.1 \,s$, then the magnitude of force exerted by the ball on the hand of the player will be (in $SI$ unit):

$A$ constant force acting on a body of mass $3.0 \, kg$ changes its speed from $2.0 \, m/s$ to $3.5 \, m/s$ in $25 \, s$. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?