Given C_1 = 2 mu F,C_2 = 6 mu F,and C_3 = 4 m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) From the circuit diagram,$C_1$ and $C_2$ are in series,and their combination is in parallel with $C_3$.First,calculate the equivalent capacitance

Vedclass · Accepted Answer

$11 	imes 10^{-6}\ J$

Vedclass · Answer

(B) From the circuit diagram,$C_1$ and $C_2$ are in series,and their combination is in parallel with $C_3$.First,calculate the equivalent capacitance of $C_1$ and $C_2$ in series:$C_{12} = \frac{C_1 C_2}{C_1 + C_2} = \frac{2 	imes 6}{2 + 6} = \frac{12}{8} = 1.5\ \mu F$.Now,$C_{12}$ is in parallel with $C_3$,so the total equivalent capacitance $C_{eq}$ is:$C_{eq} = C_{12} + C_3 = 1.5 + 4 = 5.5\ \mu F$.The total energy $U$ stored in the system is given by:$U = \frac{1}{2} C_{eq} V^2 = \frac{1}{2} 	imes 5.5 	imes 10^{-6} 	imes (2)^2$$U = \frac{1}{2} 	imes 5.5 	imes 10^{-6} 	imes 4 = 11 	imes 10^{-6}\ J$.

Given $C_1 = 2\ \mu F$,$C_2 = 6\ \mu F$,and $C_3 = 4\ \mu F$. What is the total energy of the system?

Similar Questions

$A$ parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A,$ the energy stored in the capacitor is

Energy is stored in what form in a capacitor?

An uncharged capacitor is connected to a battery. While charging the capacitor,how much is the energy lost,from the energy supplied by the battery (in $\%$)?

Three plates $A, B, C$ each of area $50 \, cm^2$ have a separation of $3 \, mm$ between $A$ and $B$ and $3 \, mm$ between $B$ and $C$. The energy stored when the plates are fully charged is (as shown in the figure):

Vedclass Test Series

Exam Paper Generator

Online Exam Module