In the given circuit,(V_A - V_B) = dots dots | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total current $I = 2 \, A$ enters at junction $D$ and splits into two branches.Let $I_1$ be the current through the upper branch $DAC$ and $I_

Vedclass · Accepted Answer

$+1$

Vedclass · Answer

(B) The total current $I = 2 \, A$ enters at junction $D$ and splits into two branches.Let $I_1$ be the current through the upper branch $DAC$ and $I_2$ be the current through the lower branch $DBC$.The resistance of the upper branch is $R_1 = 2 \, \Omega + 3 \, \Omega = 5 \, \Omega$.The resistance of the lower branch is $R_2 = 3 \, \Omega + 2 \, \Omega = 5 \, \Omega$.Since the resistances are equal,the current splits equally: $I_1 = I_2 = I / 2 = 2 \, A / 2 = 1 \, A$.Now,calculate the potentials:$V_D - V_A = I_1 	imes 2 \, \Omega = 1 \, A 	imes 2 \, \Omega = 2 \, V \implies V_A = V_D - 2 \, V$.$V_D - V_B = I_2 	imes 3 \, \Omega = 1 \, A 	imes 3 \, \Omega = 3 \, V \implies V_B = V_D - 3 \, V$.Now,find the potential difference $(V_A - V_B)$:$V_A - V_B = (V_D - 2 \, V) - (V_D - 3 \, V) = -2 \, V + 3 \, V = +1 \, V$.

In the given circuit,$(V_A - V_B) = \dots \dots \dots V$.

Similar Questions

Assertion : In a simple battery circuit,the point of the lowest potential is the negative terminal of the battery.
Reason : The current flows towards the point of the higher potential,as it does in such a circuit from the negative to the positive terminal.

$A$ cell of $e.m.f.$ $1.5\,V$ having a finite internal resistance is connected to a load resistance of $2\,\Omega$. For maximum power transfer,the internal resistance of the cell should be ............. $\Omega$.

The voltage and the current between points $A$ and $B$ shown in the circuit are . . . . . . .

For a cell, the graph between the potential difference $(V)$ across the terminals of the cell and the current $(I)$ drawn from the cell is shown in the figure. The $e.m.f.$ and the internal resistance of the cell are

Find the potential difference between $a$ and $b$,as shown in the below circuit. (in $V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module