For a common emitter transistor amplifier, the current gain is $\beta = 100$. Given the input voltage $V_{in} = 1 \text{ mV}$, input resistance $R_{in} = 1 \text{ k}\Omega$, and load resistance $R_L = 10 \text{ k}\Omega$, calculate the output voltage $V_{out}$ in $\text{V}$.

$A$ $npn$ transistor is connected in common emitter configuration in a given amplifier. $A$ load resistance of $800 \,\,\Omega$ is connected in the collector circuit and the voltage drop across it is $0.8 \,\, V$. If the current amplification factor is $0.96$ and the input resistance of the circuit is $192 \,\,\Omega$,the voltage gain and the power gain of the amplifier will respectively be

In a transistor amplifier,$\beta = 62$,$R_L = 5000\, \Omega$,and the internal resistance of the transistor is $R_i = 500\, \Omega$. The voltage amplification of the amplifier will be:

In the $CB$ mode of a transistor, when the collector voltage changes by $0.5 \ V$, the collector current changes by $0.05 \ mA$. What is the output resistance in $k\Omega$?

In the case of a transistor,what is the relationship between the current gain parameters $\alpha$ and $\beta$?

$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?