The solution set of $x \equiv 3 \pmod{7}$,where $x \in \mathbb{Z}$,is:

Let $A = \{2, 3, 4, 5\}$ and $B = \{3, 6, 7, 10\}$. $A$ relation $R$ is defined from $A$ to $B$ such that $xRy \iff x$ is relatively prime to $y$. What is the domain of $R$?

$A$ relation $R$ is defined from $\{2, 3, 4, 5\}$ to $\{3, 6, 7, 10\}$ by $xRy \iff x$ is relatively prime to $y$. Then the domain of $R$ is

Given $A = \{1, 2, 3, 4, 5\}$ and $B = \{1, 4, 5\}$. If $R$ is a relation from $A$ to $B$ such that $(x, y) \in R$ with $x > y$,then the range of $R$ is:

Let the relation $R$ be defined on the set of natural numbers $N$ by $a R b$ if $3 a+2 b=27$. Then $R$ is:

If $R$ is a relation from set $A$ to set $B$,then