Let the relation R be defined on the set of n | vedclass

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(D) Given the relation $3 a+2 b=27$ where $a, b \in N$ (natural numbers). $2 b = 27 - 3 a$ $b = \frac{3(9 - a)}{2}$ Since $b$ must be a natural number

Vedclass · Accepted Answer

$\{(1, 12), (3, 9), (5, 6), (7, 3)\}$

Vedclass · Answer

(D) Given the relation $3 a+2 b=27$ where $a, b \in N$ (natural numbers). $2 b = 27 - 3 a$ $b = \frac{3(9 - a)}{2}$ Since $b$ must be a natural number,$3(9 - a)$ must be even and positive. For $a = 1, b = \frac{3(8)}{2} = 12$. For $a = 3, b = \frac{3(6)}{2} = 9$. For $a = 5, b = \frac{3(4)}{2} = 6$. For $a = 7, b = \frac{3(2)}{2} = 3$. For $a = 9, b = 0$ (not a natural number). Thus,$R = \{(1, 12), (3, 9), (5, 6), (7, 3)\}$.

Let the relation $R$ be defined on the set of natural numbers $N$ by $a R b$ if $3 a+2 b=27$. Then $R$ is:

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