lim limits _{x to 0} frac{{{{(sin x - tan x)} | vedclass

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(C) લક્ષ $L = \lim \limits _{x 	o 0} \frac{{{{(\sin x - 	an x)}^2} - {{(1 - \cos 2x)}^4} + {x^5}}}{{7\cdot{{({{	an }^{ - 1}}x)}^7}\, + {{({{\sin }^

Vedclass · Accepted Answer

$1/3$

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(C) લક્ષ $L = \lim \limits _{x 	o 0} \frac{{{{(\sin x - 	an x)}^2} - {{(1 - \cos 2x)}^4} + {x^5}}}{{7\cdot{{({{	an }^{ - 1}}x)}^7}\, + {{({{\sin }^{ - 1}}x)}^6}+ 3{{\sin }^5}x}}$ ની ગણતરી કરવા માટે,આપણે $x 	o 0$ હોય ત્યારે મુખ્ય પદોને ધ્યાનમાં લઈએ.અંશ:$(\sin x - 	an x)^2 \approx \frac{x^6}{4}$.$(1 - \cos 2x)^4 \approx 16x^8$.તેથી,અંશ $x^5$ ને સમાન છે.છેદ:$7(	an^{-1} x)^7 + (\sin^{-1} x)^6 + 3(\sin x)^5 \approx 3x^5$.માટે,લક્ષ $L = \lim \limits _{x 	o 0} \frac{x^5}{3x^5} = \frac{1}{3}$.

$\lim \limits _{x \to 0} \frac{{{{(\sin x - \tan x)}^2} - {{(1 - \cos 2x)}^4} + {x^5}}}{{7\cdot{{({{\tan }^{ - 1}}x)}^7}\, + {{({{\sin }^{ - 1}}x)}^6}+ 3{{\sin }^5}x}}$ ની કિંમત શોધો.

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