$n$ balls each of weight $w$. When weighed in pairs,the sum of the weights of all possible pairs is $120$. When they are weighed in triplets,the sum of the weights of all possible triplets is $480$. Then $n$ is:

  • A
    $5$
  • B
    $10$
  • C
    $15$
  • D
    $20$

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