$A$ $25\, W$, $220\, V$ bulb and a $100\, W$, $220\, V$ bulb are connected in parallel across a $440\, V$ line. Which of the following will happen?

If in the circuit shown below,the internal resistance of the battery is $1.5 \, \Omega$ and $V_P$ and $V_Q$ are the potentials at $P$ and $Q$ respectively,what is the potential difference between the points $P$ and $Q$?

Assertion: In a simple battery circuit,the point of the lowest potential is the positive terminal of the battery.
Reason: The current flows towards the point of the higher potential,as it does in such a circuit from the negative to the positive terminal.

$A$ cell of emf $E$ is connected to a resistance $R_{1}$ for time $t$ and the amount of heat generated in it is $H$. If the resistance $R_{1}$ is replaced by another resistance $R_{2}$ and is connected to the cell for the same time $t$, the amount of heat generated in $R_{2}$ is $4H$. Then the internal resistance $r$ of the cell is:

The net current flowing in the given circuit is . . . . . . $\text{A}$.

$A$ uniform metallic wire of length $L$ is mounted in two configurations. In configuration $1$ (triangle),it is an equilateral triangle and a voltage $V$ is applied to corners $A$ and $B$. In configuration $2$ (circle),it is bent in the form of a circle and the potential $V$ is applied at diametrically opposite points $P$ and $Q$. The ratio of the power dissipated in configuration $1$ to configuration $2$ is