A bimetallic strip consists of metals A and B | vedclass

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(D) The change in length of a metal strip is given by $\Delta L = L \alpha \Delta T$,where $\alpha$ is the coefficient of linear expansion and $\Delta

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Bend towards the left

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(D) The change in length of a metal strip is given by $\Delta L = L \alpha \Delta T$,where $\alpha$ is the coefficient of linear expansion and $\Delta T$ is the change in temperature.Since the strip is placed in a cold bath,the temperature decreases,so $\Delta T$ is negative,meaning both metals will contract.Given that $\alpha_{A} > \alpha_{B}$,the contraction in metal $A$ will be greater than the contraction in metal $B$ (i.e.,$|\Delta L_{A}| > |\Delta L_{B}|$).Since metal $A$ is on the left and it contracts more than metal $B$,the strip will bend towards the side that contracts more,which is the left side.

$A$ bimetallic strip consists of metals $A$ and $B$. It is mounted rigidly as shown. The metal $A$ has a higher coefficient of linear expansion compared to that of metal $B$. When the bimetallic strip is placed in a cold bath,it will:

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