A block A with mass 100, kg is resting on ano | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To start moving block $B$,the applied force $F$ must overcome the frictional forces acting on it.There are two frictional forces opposing the moti

Vedclass · Accepted Answer

$1100$

Vedclass · Answer

(C) To start moving block $B$,the applied force $F$ must overcome the frictional forces acting on it.There are two frictional forces opposing the motion of block $B$:$1$. The kinetic friction between block $A$ and block $B$ $(f_{AB})$,which acts on $B$ in the direction opposite to its motion.$f_{AB} = \mu_{AB} \cdot N_A = \mu_{AB} \cdot m_A \cdot g = 0.2 	imes 100 	imes 10 = 200\, N$.$2$. The kinetic friction between block $B$ and the ground $(f_{BG})$,which acts on $B$ in the direction opposite to its motion.The normal force on the ground is the sum of the weights of both blocks: $N_G = (m_A + m_B)g = (100 + 200) 	imes 10 = 3000\, N$.$f_{BG} = \mu_{BG} \cdot N_G = 0.3 	imes 3000 = 900\, N$.Therefore,the minimum force $F$ required to move block $B$ is the sum of these two frictional forces:$F = f_{AB} + f_{BG} = 200\, N + 900\, N = 1100\, N$.

Similar Questions

In the arrangement shown in the figure,if the blocks of masses $m$ and $2m$ are released from rest,find the tension in the string. (Given: $\mu_1 = 2/3$ for mass $m$,$\mu_2 = 1/3$ for mass $2m$,the string is massless and inextensible,and the pulley is frictionless.)

$A$ ball connected with a string is released at an angle of $45^{\circ}$ with the vertical,as shown in the figure. If the mass of the box is equal to the mass of the ball,the acceleration of the box at this instant will be:

If $M_2 = 2M_1$ and $\theta = 30^\circ$,the acceleration of $M_2$ is $a$. If the positions of the blocks are interchanged,what will be the acceleration of $M_2$?

Three blocks $A, B$ and $C,$ of masses $4 \, kg, 2 \, kg$ and $1 \, kg$ respectively,are in contact on a frictionless surface,as shown. If a force of $14 \, N$ is applied on the $4 \, kg$ block,then the contact force between $A$ and $B$ is .......... $N$.

$A$ body of mass $2 \ kg$ is acted upon by two forces each of magnitude $1 \ N$ and inclined at $60^{\circ}$ with each other. The acceleration of the body in $m/s^2$ is $[\cos 60^{\circ}=0.5]$

Vedclass Test Series

Exam Paper Generator

Online Exam Module