A block is placed on a frictionless horizonta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When a block is connected to two springs on either side,any displacement $x$ of the block causes one spring to compress by $x$ and the other to st

Vedclass · Accepted Answer

$[\frac{K_1 + K_2}{m}]^{1/2}$

Vedclass · Answer

(A) When a block is connected to two springs on either side,any displacement $x$ of the block causes one spring to compress by $x$ and the other to stretch by $x$.Since both springs exert a restoring force in the same direction (opposing the displacement),the springs are effectively in a parallel configuration.The equivalent spring constant $K_{eq}$ is given by $K_{eq} = K_1 + K_2$.The angular frequency $\omega$ of a spring-mass system is given by $\omega = \sqrt{\frac{K_{eq}}{m}}$.Substituting the value of $K_{eq}$,we get $\omega = \sqrt{\frac{K_1 + K_2}{m}}$.

$A$ block is placed on a frictionless horizontal table. The mass of the block is $m$ and springs are attached on either side with force constants $K_1$ and $K_2$. If the block is displaced a little and left to oscillate,then the angular frequency of oscillation will be

Similar Questions

$A$ spring having a spring constant $K$ is loaded with a mass $m$. The spring is cut into two equal parts and one of these is loaded again with the same mass. The new spring constant is

$A$ particle of mass $m$ is attached to three identical massless springs of spring constant $k$ as shown in the figure. The time period of vertical oscillation of the particle is

The vertical extension in a light spring by a weight of $1\, kg$ suspended from it is $9.8\, cm$. What is the period of oscillation?

The frequency of oscillation of a mass $m$ suspended by a spring is $v_1$. If the length of the spring is cut to half, the same mass oscillates with frequency $v_2$. The value of $v_2/v_1$ is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module