A block of ice floats in an oil in a vessel. | vedclass

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(B) According to Archimedes' principle,the weight of the displaced oil is equal to the weight of the floating ice block.Let $V_{ice}$ be the volume of

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(B) According to Archimedes' principle,the weight of the displaced oil is equal to the weight of the floating ice block.Let $V_{ice}$ be the volume of the ice and $\rho_{ice}$ be its density. The weight of the ice is $W = V_{ice} \rho_{ice} g$.The weight of the displaced oil is $W_{oil} = V_{displaced} \rho_{oil} g$.Since the ice is floating,$W = W_{oil}$,so $V_{displaced} = V_{ice} (\rho_{ice} / \rho_{oil})$.When the ice melts,it turns into water with volume $V_{water} = V_{ice} (\rho_{ice} / \rho_{water})$.Since the density of oil $\rho_{oil}$ is generally less than the density of water $\rho_{water}$,the volume of the melted water $V_{water}$ is less than the volume of the displaced oil $V_{displaced}$.Therefore,the level of the oil in the vessel will go down.

$A$ block of ice floats in an oil in a vessel. When the ice melts,the level of oil will ..............

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