A capacitor of capacity 50,mu F is charged to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2}CV^2$.Given:Capacitance $C = 50\,\mu F = 50 	imes 10^{-6}\,F$.Potent

Vedclass · Accepted Answer

$2.5 	imes 10^{-3}\,J$

Vedclass · Answer

(A) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2}CV^2$.Given:Capacitance $C = 50\,\mu F = 50 	imes 10^{-6}\,F$.Potential difference $V = 10\;V$.Substituting the values into the formula:$U = \frac{1}{2} 	imes (50 	imes 10^{-6}) 	imes (10)^2$$U = \frac{1}{2} 	imes 50 	imes 10^{-6} 	imes 100$$U = 25 	imes 10^{-4} = 2.5 	imes 10^{-3}\,J$.Therefore,the energy stored is $2.5 	imes 10^{-3}\,J$.

$A$ capacitor of capacity $50\,\mu F$ is charged to $10\;V$. Its energy is equal to:

Similar Questions

Capacity of a capacitor is $48 \mu F$. When it is charged from $0.1 C$ to $0.5 C$,the change in the energy stored is:

How much work is required to increase the voltage of a $6\,\mu F$ capacitor from $10\ V$ to $20\ V$?

$A$ capacitor of $6 \ \mu F$ is charged from $10 \ V$ to $20 \ V$. The increase in its stored energy is:

In the circuit shown in the figure,four capacitors are connected to a battery. The maximum energy is stored in the capacitor of.....$\mu F$

The work done in placing a charge of $8 \times 10^{-18} \, C$ on a condenser of capacity $100 \, \mu F$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module