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(D) The magnetic flux $\phi$ linked with the loop is given by $\phi = B \cdot A$,where $A$ is the area of the loop inside the magnetic field. Since th

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(D) The magnetic flux $\phi$ linked with the loop is given by $\phi = B \cdot A$,where $A$ is the area of the loop inside the magnetic field. Since the magnetic field $B$ is uniform and constant,and the entire loop is moving within the region where the magnetic field exists,the area $A$ of the loop enclosed by the magnetic field remains constant. As the magnetic flux $\phi = B \cdot A$ does not change with time,the rate of change of magnetic flux $d\phi/dt$ is zero. According to Faraday's law of electromagnetic induction,the induced electromotive force $(EMF)$ is $\varepsilon = -d\phi/dt$. Since $d\phi/dt = 0$,the induced $EMF$ $\varepsilon = 0$. Consequently,the induced current $I = \varepsilon/R = 0$. Therefore,no current is induced in the loop.

$A$ conducting square loop of side $l$ and resistance $R$ moves in its plane with a uniform velocity $v$ perpendicular to one of its sides. $A$ uniform and constant magnetic field $B$ exists perpendicular to the plane of the loop as shown in the figure. The current induced in the loop is

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