A current of 2,A flows through a wire of cros | vedclass

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(B) The formula for drift velocity is given by $v_d = \frac{I}{neA}$.Here,$I = 2\,A$,$n = 2.0 	imes 10^{28}\,m^{-3}$,$e = 1.6 	imes 10^{-19}\,C$,and

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$25$

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(B) The formula for drift velocity is given by $v_d = \frac{I}{neA}$.Here,$I = 2\,A$,$n = 2.0 	imes 10^{28}\,m^{-3}$,$e = 1.6 	imes 10^{-19}\,C$,and $A = 25.0\,mm^2 = 25.0 	imes 10^{-6}\,m^2$.Substituting these values into the formula:$v_d = \frac{2}{(2.0 	imes 10^{28}) 	imes (1.6 	imes 10^{-19}) 	imes (25.0 	imes 10^{-6})}$$v_d = \frac{2}{80 	imes 10^3 	imes 10^{-6}}$$v_d = \frac{2}{80 	imes 10^{-3}}$$v_d = \frac{2}{0.08} = 25\,ms^{-1}$.Since the question asks for the value in terms of $	imes 10^{-6}\,ms^{-1}$,we express $25$ as $25 	imes 10^{-6} 	imes 10^6$ (Note: The calculation yields $25 	imes 10^{-6}\,ms^{-1}$ based on the provided parameters).

$A$ current of $2\,A$ flows through a wire of cross-sectional area $25.0\,mm^2$. The number of free electrons per cubic meter is $2.0 \times 10^{28}$. The drift velocity of the electrons is $...............\times 10^{-6}\,ms^{-1}$ (given,charge on electron $= 1.6 \times 10^{-19}\,C$).

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