A dealer bought x^{2}+2x+3 pieces of mobiles | vedclass

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Question

(A) To find the price of one mobile,we divide the total cost by the number of pieces bought.Price of one mobile = $\frac{x^{3}+6x^{2}+11x+12}{x^{2}+2x

Vedclass · Accepted Answer

$x+4$

Vedclass · Answer

(A) To find the price of one mobile,we divide the total cost by the number of pieces bought.Price of one mobile = $\frac{x^{3}+6x^{2}+11x+12}{x^{2}+2x+3}$.Performing polynomial long division:$1$. Divide the first term of the dividend $(x^3)$ by the first term of the divisor $(x^2)$ to get $x$.$2$. Multiply $x$ by the divisor: $x(x^{2}+2x+3) = x^{3}+2x^{2}+3x$.$3$. Subtract this from the dividend: $(x^{3}+6x^{2}+11x+12) - (x^{3}+2x^{2}+3x) = 4x^{2}+8x+12$.$4$. Divide the first term of the remainder $(4x^2)$ by the first term of the divisor $(x^2)$ to get $4$.$5$. Multiply $4$ by the divisor: $4(x^{2}+2x+3) = 4x^{2}+8x+12$.$6$. Subtract this from the remainder: $(4x^{2}+8x+12) - (4x^{2}+8x+12) = 0$.Therefore,the price of one mobile is $x+4$.

$A$ dealer bought $x^{2}+2x+3$ pieces of mobiles for Rs. $x^{3}+6x^{2}+11x+12$. Find the price of one mobile.

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