A diseased man marries a normal woman. They g | vedclass

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(D) In this scenario,the father is diseased and the mother is normal. All daughters inherit the $X$ chromosome from their father,while all sons inheri

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Sex linked dominant

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(D) In this scenario,the father is diseased and the mother is normal. All daughters inherit the $X$ chromosome from their father,while all sons inherit the $Y$ chromosome from their father. Since all daughters are diseased and all sons are normal,the disease-causing gene must be located on the $X$ chromosome inherited from the father. Because the trait is expressed in all daughters (who receive the $X$ chromosome from the father),it indicates that the gene is $X$-linked dominant. If it were $X$-linked recessive,the daughters would be carriers but not necessarily diseased unless the mother was also a carrier or affected. Therefore,the pattern of inheritance is $X$-linked dominant.

$A$ diseased man marries a normal woman. They get three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease is

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